Answer:
342 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 185 mL
Initial temperature (T₁) = 45 °C
Final temperature (T₂) = 109 °C
Final volume (V₂) =?
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T₁) = 45 °C
Initial temperature (T₁) = 45 °C + 273
Initial temperature (T₁) = 318 K
Final temperature (T₂) = 109 °C
Final temperature (T₂) = 109 °C + 273
Final temperature (T₂) = 382 K
Finally, we shall determine the final volume of the gas as follow:
Initial volume (V₁) = 185 mL
Initial temperature (T₁) = 318 K
Final temperature (T₂) = 382 K
Final volume (V₂) =?
V₁/T₁ = V₂/T₂
285 / 318 = V₂ / 382
Cross multiply
318 × V₂ = 285 × 382
318 × V₂ = 108870
Divide both side by 318
V₂ = 108870 / 318
V₂ ≈ 342 mL
Therefore, the new volume of the gas is 342 mL
