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Sagot :
Answer:
a. 36 ft
b. Maximum height is reached in 1.5 sec.
c. Maximum height is 40 ft
d. 3.08 sec
Step-by-step explanation:
a. h = -16(2)^2+ 48(2) + 4
= -64 + 96 + 4 = 36 ft
b. Maximum height is at the vertex of the parabola.
Let (h, k) be the vertex.
h = -b/2a = - 48/-32 = 3/2 = 1.5
k = -16(1.5)^2 + 48(1.5) +4
-36 + 72 + 4 = 40
Vertex is (1.5, 40) 1.5 is the time it takes to reach maximum height and 40 is the maximum height
Maximum height is reached in 1.5 sec.
c. Maximum height is 40 ft
d. The 4 in the equation tells us that the ball was thrown initially from a height of 4 ft.
When the ball hits the ground, h(t) = 0
-16t^2+48t+4 = 0
-4(4t^2 - 12t - 1) = 0
Use the quadratic formula to solve for t
t = 3.08 sec
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