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Which equation represents the line shown on the coordinate plane below??

Which Equation Represents The Line Shown On The Coordinate Plane Below class=

Sagot :

The y-intercept=0 and the slope=-1/4,
so y=-1/4x represents the line.

A straight line is represented by a linear function.

The equation of the line is [tex]y = -\frac 14 x[/tex]

From the coordinate plane, the line passes through the following points

[tex](x,y) =(0,0)\ (4,-1)[/tex]

The slope of the above points is calculated using:

[tex]m = \frac{y_2 -y_1}{x_2 -x_1}[/tex]

So, the above equation becomes

[tex]m = \frac{-1 - 0}{4-0}[/tex]

This gives

[tex]m = \frac{-1}{4}[/tex]

Rewrite as:

[tex]m = -\frac{1}{4}[/tex]

The line equation is then calculated as:

[tex]y = m(x-x_1) + y_1[/tex]

So, we have:

[tex]y = -\frac 14 (x-0) + 0[/tex]

This gives

[tex]y = -\frac 14 (x)[/tex]

Remove bracket

[tex]y = -\frac 14 x[/tex]

Hence, the equation of the line is [tex]y = -\frac 14 x[/tex]

Read more about line equations at:

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