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what is the equation of a circle with center (2,-3) and radius 3?

What Is The Equation Of A Circle With Center 23 And Radius 3 class=

Sagot :

Answer: The answer is A

Step-by-step explanation:

Equation of a circle: (x-a)^2+(y-b)^2=r^2, where a and b are the coordinates of a center, r - radius

So, you have (2,-3) as a center, and radius r is 3.

Then, your equation is (x-2)^2+(y+3)^2=9

the equation of a circle with center at (h,k) and radius of r is

(x-h)^2+(y-k)^2=r^2

so

(2,-3) and radius is 3

(x-2)^2+(y-(-3))^2=3^2

(x-2)^2+(y+3)^2=9

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