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The pressure on a sample of gas is increased from 1.0 atm to 3.0 atm. If the new volume is 0.52 L, find the original volume.

Sagot :

keijosalonen

Answer: 1.56 ATM

Explanation: if we assume temperature is constant, gas obeys

Boyles law pV= constant. Then p1·V1= p2·V2. And V1 = p2V2/p1

= 3.0 atm·0,52 l / 1.0 atm

nuhulawal20

The initial or original volume of the gas with pressure increased to the given value is 1.56L.

Boyle's law

Boyle's law states that "the volume V of a given quantity of gas is inversely proportional to its pressure P as long as temperature remains constant.

It is expressed as;

P₁V₁ = P₂V₂

Given the data in the question;

  • Initial pressure P₁ = 1.0atm
  • Final pressure P₂ = 3.0atm
  • Final volume V₂ = 0.52L
  • Initial Volume V₁ = ?

To determine the initial volume of the gas, we substitute our given values into the expression above.

P₁V₁ = P₂V₂

V₁ = P₂V₂ / P₁

V₁ = ( 3.0atm × 0.52L ) / 1.0atm

V₁ = 1.56Latm / 1.0atm

V₁ = 1.56L

Therefore, the initial or original volume of the gas with pressure increased to the given value is 1.56L.

Learn more about Boyle's law here: brainly.com/question/1437490

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