At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:
{-8, -4}
Step-by-step explanation:
Rewrite this function y=x2 +12x +32 as y = x^2 + 12x + 32; " ^ " indicates exponentiation.
Set this x^2 + 12x + 32 equal to zero (to find the zeros):
x^2 + 12x + 32 = 0. Let's solve this using the quadratic formula, which applies when ax^2 + bx + c = 0:
-b ± √(b^2 - 4·a·c)
x = -------------------------------
2a
The coefficients of the given quadratic are {1, 12, 32}. Thus, the discriminant is
b^2 - 4ac, or 12^2 - 4(1)(32), or 144 - 128, or 16. Therefore, we have:
-12 ± √16 -12 ± 4
x = -------------------- which simplifies to: x = --------------- = { -8, -4}
2 2
The zeros are {-8, -4}
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.