Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

The following if statement tests the rainfall in New York’s Central Park during the months of June, July and August.

if (low <= rain && rain <= high)
System.out.println("Rainfall amount is normal.");
else
System.out.println("Rainfall amount is abnormal.");
It could be replaced with:
I.

if (rain >= low)
{
if (rain <= high)
System.out.println("Rainfall amount is normal.");
}
else
System.out.println("Rainfall amount is abnormal.");
II.

if (rain >= low)
{
if (rain <= high)
System.out.println("Rainfall amount is normal.");
else
System.out.println("Rainfall amount is abnormal.");
}
else
System.out.println("Rainfall amount is abnormal.");
III.

if (rain >= low)
System.out.println("Rainfall amount is normal.");
else if (rain <= high)
System.out.println("Rainfall amount is normal.");
else
System.out.println("Rainfall amount is abnormal.");
I only
II only
III only
(II or III)
I, II or III

Sagot :

Jamesanny20

Answer:

II only

Explanation:

In the original code, both conditions of low<=rain and rain >= high must be met for the print message to be executed. This is denoted by the && logical operator.

The code in II does the same thing. It first checks that the low <=rain condition is true; then it goes on to check if the rain >= high condition is true as well before the "normal" print statement can be executed. But if either of the condition is not true, it prints "abnormal" because both conditions must be true.

Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.