Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Two girls are standing 100 feet apart they both see a beautiful seagull in the air between them the angles of elevation from the girls to the bird are 20 degrees and 45 degrees respectively how high up is the seagull

Sagot :

boffeemadrid

Answer:

[tex]26.68\ \text{feet}[/tex]

Step-by-step explanation:

a = 100 feet

[tex]\angle B=20^{\circ}[/tex]

[tex]\angle C=45^{\circ}[/tex]

[tex]\angle A=180-(20+45)=115^{\circ}[/tex]

From sine rule we have

[tex]\dfrac{\sin B}{b}=\dfrac{\sin A}{a}\\\Rightarrow b=\dfrac{\sin B}{\sin A}a\\\Rightarrow b=\dfrac{\sin 20^{\circ}}{\sin 115^{\circ}}\times 100\\\Rightarrow b=37.73\ \text{feet}[/tex]

[tex]\sin C=\dfrac{h}{b}\\\Rightarrow h=b\sin C\\\Rightarrow h=37.73\times \sin 45^{\circ}\\\Rightarrow h=26.68\ \text{feet}[/tex]

The is seagull is [tex]26.68\ \text{feet}[/tex] above the ground.

View image boffeemadrid
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.