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The cost of 2 jackets and 3 skirts was sh 1800. After the cost of a jacket and that of a skirt was increased by 20%,the cost of 6 jackets and 2 skirts was sh4800,what is the new cost of a jacket and that of a skirt

Sagot :

boffeemadrid

Answer:

New cost of jacket = [tex]1.2x=1.2\times 600=720\ \text{sh}[/tex]

New costs of skirt = [tex]1.2y=1.2\times 200=240\ \text{sh}[/tex]

Step-by-step explanation:

Let original cost of jacket = [tex]x[/tex]

original cost of skirt = [tex]y[/tex]

The equation will be

[tex]2x+3y=1800[/tex]

New cost of jacket = [tex]1.2x[/tex]

New costs of skirt = [tex]1.2y[/tex]

The equation will be

[tex]6(1.2x)+2(1.2y)=4800\\\Rightarrow 7.2x+2.4y=4800[/tex]

The equations are

[tex]2x+3y=1800[/tex]  [tex]\times 0.8[/tex]

[tex]7.2x+2.4y=4800[/tex]

[tex]1.6x+2.4y=1440[/tex]

[tex]7.2x+2.4y=4800[/tex]

Subtracting the above two equations we get

[tex]-5.6x=-3360\\\Rightarrow x=\dfrac{3360}{5.6}\\\Rightarrow x=600[/tex]

[tex]7.2\times 600+2.4y=4800\\\Rightarrow y=\dfrac{4800-7.2\times 600}{2.4}\\\Rightarrow y=200[/tex]

New cost of jacket = [tex]1.2x=1.2\times 600=720\ \text{sh}[/tex]

New costs of skirt = [tex]1.2y=1.2\times 200=240\ \text{sh}[/tex].

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