Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
Part a [5522.3511 ; 5727.8488]
Part b. The p-value is 0.050115.
The H0 is rejected and concluded that the true mean life of a biomedical device is greater than 5500.
Step-by-step explanation:
The 95 % confidence interval for the mean of the population is given by
∝= 1- 0.95= 0.05
υ= n-1= 15-1= 14
x`± t ∝() s / √n
5625.1 ± { t (0.05) (14)} 226.1 / √15
5625.1 ± 1.76 * 226.1/3.8729
5625.1 ± 102.7488
[5522.3511 ; 5727.8488]
Part b
State the null and the alternate hypothesis
H0: u= 5500 against the claim Ha: u > 5500
the test statistic
t= x`- u/ s/ √n
t= 5625.1-5500/226.1 / √15
t=2.143
The p-value is 0.050115.
The result is not significant at p < 0.05.
The H0 is rejected and concluded that the true mean life of a biomedical device is greater than 5500.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.