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A square sits with its lower left corner at the orgin the square is translated five units up and seven units to the right what are the coordinates of the lower left corner of the square after translation

Sagot :

Answer:

[tex](2,0)[/tex]

Step-by-step explanation:

Given

The initial lower left corner of the square at:

[tex](x,y) = (0,0)[/tex]

Required

Its new position after 5 units left and 7 units right translations

When a point is translated to the left by a units, the rule is:

[tex](x,y) ==> (x-a,y)[/tex]

In this case:

[tex]a = 5[/tex]

So:

[tex](0,0) ==> (0-5,0)[/tex]

[tex](0,0) ==> (-5,0)[/tex]

So, the new point is: (-5,0)

When a point is translated to the right by b units, the rule is:

[tex](x,y) ==> (x+b,y)[/tex]

In this case:

[tex]b = 7[/tex]

So:

[tex](-5,0)= (-5+7,0)[/tex]

[tex](-5,0)= (2,0)[/tex]

So, the new point is: (2,0)