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When he was measuring herbs on his balance scale, Neville placed a 1/2 gram weight, then a 1/5 gram weight, and finally a 1/8 gram weight before the scale balanced. How much did his herbs weigh?

Sagot :

Answer:  [tex]\dfrac{33}{40}\ gm[/tex]

Step-by-step explanation:

Given

Neville place three weights in the sequence

[tex]\dfrac{1}{2}\ gm,\dfrac{1}{5}\ gm,\dfrac{1}{8}\ gm[/tex]

The total weight of the three weights is

[tex]\Rightarrow \dfrac{1}{2}+\dfrac{1}{5}+\dfrac{1}{8}=\dfrac{20+8+5}{40}\\\\\Rightarrow \dfrac{33}{40}\ gm[/tex]

Thus, herbs weigh  [tex]\frac{33}{40}\ gm[/tex]

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