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Solve for x pls and thank you

Solve For X Pls And Thank You class=

Sagot :

Answer:

x= 12

Step-by-step explanation:

∠QPR +∠PQR= ∠HRQ (ext. ∠ of △PQR)

30° +(4x +2)°= (8 +6x)°

32 +4x= 8 +6x (simplify)

Bring x terms on 1 side, constants to the other:

6x -4x= 32 -8

2x= 24 (simplify)

x= 24 ÷2 (÷2 on both sides)

x= 12

Method 2:

∠PRQ= 180° -30° -(4x +2)° (∠ sum of △PQR)

∠PRQ= (148 -4x)°

∠PRQ +∠HRQ= 180° (adj. ∠s on a str. line)

(148 -4x)° +(8 +6x)°= 180°

148 -4x + 8 +6x= 180

156 +2x= 180

2x= 180 -156

2x= 24

x= 24 ÷2

x= 12