Answered

Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

If a fair die is rolled twice and two numbers X1=result of the first roll and X2=result of the second roll are obtained. Given that X1+X2=7, what is the probability that X1 =4 or X2 =4

Sagot :

facundo3141592

Answer:

P = 2/3 = 0.67

Step-by-step explanation:

Assuming that X1 + X2 = 7

The total number of outcomes such that X1 + X2 = 7 are:

X1 = 3, X2 = 4

X1 = 4, X2 = 3

X1 = 1, X2 = 6

X1 = 6, X2 = 1

X1 = 2, X2 = 5

X1 = 5, X2 = 2

So there are 6 total outcomes such that X1 + X2 = 7

Now, the probability that X1 = 4 is equal to the quotient between the number of outcomes where X1 = 4 (only one outcome) and the total number of outcomes (6)

Then:

p = 1/6

And the probability that X2 = 4 is calculated in the same way, then the probability is:

q = 1/6

Now, the probability that X1 = 4 or X2 = 4 is the sum of both probabilities we've found above, then:

P = p + q = 1/6 + 1/6 = 2/6 = 2/3 = 0.67

We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.