Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Factor x3y6 + 27z42. (xy3 + 3z39)(x2y9 – 3xy3z39 + 9z1,521) (xy3 + 3z39)(x2y6 – 3xy3z39 + 9z78) (x3y6 + 27z42)(x6y12 – 27x3y6z42 + 729z84) (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28)

Sagot :

MrRoyal

Answer:

[tex]x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})[/tex]

Step-by-step explanation:

Given

[tex]x^3y^6 + 27z^{42[/tex]

Required

Factor

Express both terms as a cube

[tex]x^3y^6 + 27z^{42} = (xy^2)^3 + (3z^{14})^3[/tex]

Let

[tex]a =(xy^2)[/tex]

[tex]b = (3z^{14})[/tex]

So:

[tex]x^3y^6 + 27z^{42} = a^3 + b^3[/tex]

Using sum of cubes:

[tex]a^3 + b^3 = (a + b)(a^2 - ab + b^2)[/tex]

So:

[tex]x^3y^6 + 27z^{42} = (a + b)(a^2 - ab + b^2)[/tex]

Substitute in, values of a and b

[tex]x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})((xy^2)^2 - (xy^2)*(3z^{14}) + (3z^{14})^2)[/tex]

[tex]x^3y^6 + 27z^{42} = (xy^2 + 3z^{14})(x^2y^4 - 3xy^2z^{14} + 9z^{28})[/tex]

Answer:

its d

Step-by-step explanation:

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.