Answered

Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A centrifuge in a medical laboratory rotates at an angular speed of 3600 rev/min. When switched off, it rotates through 52.0 revolutions before coming to rest. Find the constant angular acceleration of the centrifuge.

Sagot :

boffeemadrid

Answer:

[tex]-217.508\ \text{rad/s}^2[/tex]

Explanation:

[tex]\omega_i[/tex] = Initial angular velocity = [tex]3600\times\dfrac{2\pi}{60}=377\ \text{rad/s}[/tex]

[tex]\theta[/tex] = Angular displacement = [tex]52\ \text{rev}=52\times 2\pi=326.72\ \text{rad}[/tex]

[tex]\omega_f[/tex] = Final angular velocity = 0

[tex]\alpha[/tex] = Angular acceleration

From the kinematic equations of angular motion we have

[tex]\omega_f^2-\omega_i^2=2\alpha\theta\\\Rightarrow \alpha=\dfrac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\dfrac{0-377^2}{2\times 326.72}\\\Rightarrow \alpha=-217.508\ \text{rad/s}^2[/tex]

The constant angular acceleration of the centrifuge is [tex]-217.508\ \text{rad/s}^2[/tex].

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.