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Sagot :
Answer:
The answer is "0.274 and 0.841"
Step-by-step explanation:
Given:
In this question, let X the binomial random variable with the parameters:
[tex]n = 1000\\\\P = 0.193[/tex]
Calculating the random variable Z:
[tex]Z= \frac{X - np}{\sqrt{np(l - p)}}=\frac{x -193}{12.48}[/tex]
is an approximately regular, cumulative random variable with [tex]\Phi[/tex] specified in the back of the book in the tables.
Using the continuity and tables to calculate:
[tex]\to \mathbb{P} (X > 200) = \mathbb{P} (X\geq 200.5) \approx \mathbb{P}(Z\geq 0.6)=1- \Phi(0.6) \approx 0.274 \\\\\to \mathbb{P} (180 < X < 300) = \mathbb{P} (180.5 \leq X \leq 299.5) = \approx \mathbb{P} (-1 \leq Z\leq 8.53) = \approx 1- \Phi(-1) \approx 0.841[/tex]
(a) The probability that more than 200 persons throughout the sample have a disability will be "0.08691".
(b) The probability that between 180 - 300 people throughout the sample have a disability will be "0.85122".
Probability
According to the question,
Majority percentage, P = 19.3% or,
= 0.193
Sample person, n = 1000
Q = 1 - P
= 1 - 0.193
= 0.807
By using Normal approx. to Binomial,
→ Mean, E(X) = n × P
By substituting the values,
= 1000 × 0.193
= 193
Standard deviation, X = √n × p × Q
= √1000 × 0.193 × 807
= 12.4800
(a)
Z = [tex]\frac{X - \mu}{\sigma}[/tex]
= [tex]\frac{210-193}{12.48}[/tex]
= 1.36
The probability be:
→ P(X > 210) = 1 - P (Z < 1.36)
= 1 - 0.9131
= 0.08691
(b)
Z = [tex]\frac{X - \mu}{\sigma}[/tex]
= [tex]\frac{180-193}{12.48}[/tex] or, [tex]\frac{300-193}{12.48}[/tex]
= 8.57
hence,
The probability be:
→ P (180 < X < 300) = P(Z < 8.57) - P(Z < -1.04)
= 1 - 0.1488
= 0.85122
Thus the answers above are correct.
Find out more information about probability here:
https://brainly.com/question/24756209
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