Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

An object has a volume of 4.0 m3 and weighs 40,000 N. What will its apparent weight be in water of density 1000 kg/m3?

Sagot :

pstnonsonjoku

Answer:

O N

Explanation:

Upthrust = Volume of object * density of fluid * acceleration due to gravity

Upthrust = 4.0 m3 *  1000 kg/m3 * 10 m/^2

Upthrust = 40, 000 N

Upthrust = Weight in air - Weight in water

Weight in air = 40,000 N

Weight in water = Weight in air - Upthrust

Weight in water = 40,000 N - 40,000 N

Weight in water = 0 N

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.