Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

An object has a volume of 4.0 m3 and weighs 40,000 N. What will its apparent weight be in water of density 1000 kg/m3?

Sagot :

pstnonsonjoku

Answer:

O N

Explanation:

Upthrust = Volume of object * density of fluid * acceleration due to gravity

Upthrust = 4.0 m3 *  1000 kg/m3 * 10 m/^2

Upthrust = 40, 000 N

Upthrust = Weight in air - Weight in water

Weight in air = 40,000 N

Weight in water = Weight in air - Upthrust

Weight in water = 40,000 N - 40,000 N

Weight in water = 0 N

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.