Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Calculate the number of grams of aluminum chloride produced when 8.6 moles of aluminum react with chlorine gas.
2 Al + 3 Cl2 -> 2 AlCl3

Sagot :

samueladesida43

Answer:

1148 grams

Explanation:

The balanced chemical reaction of this question is as follows:

2Al + 3Cl2 → 2AlCl3

Based on the equation above;

2 moles of Aluminum react to produce 2 moles of Aluminum chloride (AlCl3)

Therefore, 8.6 moles of aluminum will react to produce: 8.6 × 2/2

= 8.6moles of AlCl3.

Using mole = mass ÷ molar mass, to determine the number of grams.

Molar Mass of AlCl3 = 27 + 35.5(3)

= 27 + 106.5

= 133.5g/mol

Using mole = mass/molar mass

Mass = molar mass × mole

Mass = 133.5 × 8.6

Mass = 1148.1

Mass of AlCl3 = 1148 grams

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.