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Sagot :
Answer:
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O
Explanation:
Let's consider the reaction between acetic acid and strontium hydroxide. This is a neutralization reaction, in which an acid reacts with a base to form salt and water. The unbalanced equation is:
HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O
We have 1 acetate ion to the left and 2 to the right, so we will multiply HC₂H₃O₂(aq) by 2.
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + H₂O
Finally, we multiply water by 2 to get the balanced equation.
2 HC₂H₃O₂(aq) + Sr(OH)₂(aq) ⇒ Sr(C₂H₃O₂)₂(aq) + 2 H₂O
The balanced chemical equation will be
[tex]\rm \bold{2\;HC_2H_3O_2\;+\;Sr(OH)_2\;\rightarrow\;Sr(C_2H_3O_2)_2\;+\;2\;H_2O}[/tex]
A balanced equation can be considered as the one in which the number of molecules of each element on the product and the reactant side is equal.
The given reaction has been in between the strontium hydroxide and acetic acid. The neutralization reaction will result in the formation of salt and water.
The reaction can be as follows:
[tex]\rm HC_2H_3O_2\;+\;;Sr(OH)_2\;\rightarrow\;Sr(C_2H_3O_2)_2\;+\;H_2O[/tex]
The equation has equal strontium at both the product and reactant sides.
The equation has 1 acetate and 2 oxygen at the reactant side, while 2 acetates and 1 oxygen at the product side.
This can be balanced by multiplying the acetate at the reactant side with 2, and water at the product side with 2. This will balance the number of hydrogen, oxygen, acetate, and strontium in the equation.
The balanced chemical equation will be:
[tex]\rm \bold{2\;HC_2H_3O_2\;+\;Sr(OH)_2\;\rightarrow\;Sr(C_2H_3O_2)_2\;+\;2\;H_2O}[/tex]
For more information about the balanced chemical equation, refer to the link:
https://brainly.com/question/21049751
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