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Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square.

Sagot :

Answer:

x = -1, 7

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

x² - 6x - 7 = 0

Step 1,

Isolate the constant by ADDING 7 both the sides of the equation.

x² - 6x - 7 + 7 = 0 + 7

x² - 6x = 7

Step 2

Add 9 to both sides of x² - 6x = 7 to form a perfect square trinomial while keeping the equation balanced.

x² - 6x + 9 = 7 + 9

Step 3

Write the trinomial x² - 6x + 9 as (x - 3) squared.

x² - 2(3)x + 9 = 16

(x - 3)² = 4²

Step 4

Use the square root property of the equality to get x - 3 = ± 4

(x - 3)² = 4²

[tex]\sqrt{(x-3)^2}=\sqrt{4^2}[/tex]

(x - 3) = ±4

Step 5

Isolate the variable to get solution of -1 and 7

x - 3 = ± 4

x = -3 ± 4

x = -1, 7

View image eudora

Answer:

1. Isolate the constant by adding 7 to both sides of the equation.

2. Add 9 to both sides of x2 – 6x = 7 to form a perfect square trinomial while keeping the equation balanced.

3. Write the trinomial x2 – 6x + 9 as  x – 3 squared.

4. Use the square root property of equality to get x – 3 = ± 4.

5. Isolate the variable to get solutions of –1 and 7.

Step-by-step explanation:

just completed this on edge

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