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Sagot :
Solution :
Let A = Economics, B = Mathematics
n(A) = 311, n(B) = 243, [tex]$n(A \cap B) = 135$[/tex]
a). So, [tex]$n(A \cup B) = n(A) +n(B) - n(A \cap B)$[/tex]
= 311 + 243 - 135
= 419
b). n(A only) = 311 - 135
= 176
n(B only) = 243 - 135
= 108
Exactly one of these two courses
[tex]$=\frac{176+108}{500}$[/tex]
= 0.568
c). Neither economics nor mathematics
[tex]$=\frac{500-419}{500} $[/tex]
[tex]$=\frac{81}{500}$[/tex]
= 0.162
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