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Sagot :
Answer:
[tex]\mathbf{H_o: \mu_F -\mu_s = 0} \\ \\ \mathbf{H_a: \mu_F -\mu_s >0}[/tex]
Step-by-step explanation:
From the given information:
[tex]\text{The claim is that a reporter is responsible for the food section of a }[/tex][tex]\text{magazine investigated the belief that grocery stores sell beef at a higher}[/tex][tex]\text{ price in the fall than spring;}[/tex]
i.e
[tex]\mu_F > \mu_s[/tex]
Thus;
[tex]\mu_F - \mu_s >0\\[/tex]
∴
[tex]\text{The null and alternative hypothesis for the reporters investigation is:}[/tex]
[tex]\mathbf{H_o: \mu_F -\mu_s = 0} \\ \\ \mathbf{H_a: \mu_F -\mu_s >0}[/tex]
The null and alternative hypothesis for the reporter's investigation is
[tex]\rm H_o: \mu_F - \mu_s = 0 \\\\ H_a : \mu_F - \mu_s > 0[/tex]
What is a standard deviation?
It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
What is Mean?
Mean is simply defined as the average of the given set of numbers. The mean is considered as one of the measures of central tendencies in statistics.
A reporter responsible for the food section of a magazine investigated the belief that grocery stores sell beef at a higher price in the fall than in the spring.
The reporter selected independent random samples of grocery-store beef prices in November and April and computed the mean and standard deviation for the samples.
The claim is that a reporter is responsible for the food section of a magazine investigated the belief that grocery stores sell beef at a higher price in the fall than in spring. That is given as
[tex]\rm \mu_F > \mu_s \\\\\mu_F - \mu_s > 0[/tex]
Therefore, the null and alternative hypothesis for the reporter's investigation is
[tex]\rm H_o: \mu_F - \mu_s = 0 \\\\ H_a : \mu_F - \mu_s > 0[/tex]
More about the standard deviation and the mean link is given below.
https://brainly.com/question/14019792
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