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Sagot :
Answer:
[tex]H_0 : \mu_1 - \mu_2 = 0[/tex]
[tex]H_a : \mu_1 - \mu_2 \ne 0[/tex]
Step-by-step explanation:
Let the salted package be represented with 1 and the unsalted, 2.
So:
[tex]\mu_1:[/tex] Mean of salted package
[tex]\mu_2:[/tex] Mean of unsalted package
Considering the given options, the null hypothesis is that which contains =.
So, the null hypothesis is:
[tex]H_0 : \mu_1 - \mu_2 = 0[/tex]
The opposite of = is [tex]\ne[/tex]. So, the alternate hypothesis, is that which contains [tex]\ne[/tex]
So, the alternate hypothesis is:
[tex]H_a : \mu_1 - \mu_2 \ne 0[/tex]
By applying basic meaning of mean and standard deviation we got that correct null and alternative hypotheses to test the complaint’s claim are
(i) [tex]\mu_{1}-\mu_{2} =0[/tex] ; [tex]\mu1 - \mu2 > 0.[/tex] and (ii) [tex]\mu_{1}-\mu_{2} =0[/tex] ; [tex]\mu1 - \mu2 < 0.[/tex]
What is standard deviation?
Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value
Let assume that salted package are represented by 1 and the unsalted are represented by 2 .
So Mean of salted package is [tex]\mu_{1}[/tex]
and Mean of unsalted package is [tex]\mu_{2}[/tex]
Now the null hypothesis is that which contains same mean for both types
[tex]\mu_{1}=\mu_{2}\\\\\mu_{1}-\mu_{2}=0[/tex]
And alternative hypotheses is that which contains different mean for both types
[tex]\mu_{1} \neq \mu_{2}\\\\\mu_{1}-\mu_{2} \neq 0[/tex]
Hence two case are possible for alternative hypotheses
(i) [tex]\mu1 - \mu2 > 0.[/tex]
(ii) [tex]\mu1 - \mu2 < 0.[/tex]
By applying basic meaning of mean and standard deviation we got that correct null and alternative hypotheses to test the complaint’s claim are
(i) [tex]\mu_{1}-\mu_{2} =0[/tex] ; [tex]\mu1 - \mu2 > 0.[/tex] and (ii) [tex]\mu_{1}-\mu_{2} =0[/tex] ; [tex]\mu1 - \mu2 < 0.[/tex]
To learn more about standard deviation visit :https://brainly.com/question/12402189
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