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Sagot :
Answer:
Workdone = 4900joules
Step-by-step explanation:
Work-done = force x distance
Force = mass x acceleration
If we suppose that the aquarium is at height 0 at the top and height 1 at the bottom (since it's 1m deep), then we need to lift the slide at height x by x metres.
Mass = Density x Volume, therefore force needed to lift the slice is given is
F = density*volume*∆x*acceleration
Since we the mass changes as we take out water then there will be a change in height, for this reason we have ∆x.
Acceleration is due to gravity, therefore g=9.8m/s²
Density = 1000kg/m³
Volume = 4*1*1 = 4m³
F = 1000*4*∆x*9.8 = 39200∆x
Since our distance from the top of the aquarium to the bottom is x metres, then
Work-done = 39200x∆x
To find the total workdone, we find the integral of 39200xdx and the limit will be from 0 to 0.5 since we are to pump halfway of the aquarium. Integrating that we have
19600*x² limit from 0 to 0.5
19600(0.5² – 0²) = 19600(0.25 – 0) = 19600(0.25) = 4900joules
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