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The reaction for the decomposition of ammonia (NH 3 ) can be written as shownIf a student starts with 95.7 g of NH 3 , how many grams of hydrogen (H 2 ) will be produced by the reaction?

Sagot :

dsdrajlin

Answer:

17.0 g

Explanation:

Step 1: Write the reaction for the decomposition of ammonia

2 NH₃(g) ⇒ N₂(g) + 3 H₂(g)

Step 2: Calculate the moles corresponding to 95.7 g of NH₃

The molar mass of NH₃ is 17.03 g/mol.

95.7 g × 1 mol/17.03 g = 5.62 mol

Step 3: Calculate the moles of H₂ produced from 5.62 moles of NH₃

The molar ratio of NH₃ to H₂ is 2:3. The moles of H₂ produced are 3/2 × 5.62 mol = 8.43 mol.

Step 4: Calculate the mass corresponding to 8.43 moles of H₂

The molar mass of H₂ is 2.02 g/mol.

8.43 mol × 2.02 g/mol = 17.0 g

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