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Half life of first order reaction is 3 hrs. what percentage reaction is completed in 9hrs ?​

Sagot :

Answer:

92.6%

Explanation:

Hello there!

In this case, according to the first-order kinetics, we can write:

[tex]\frac{A}{Ao}=exp(-kt)[/tex]

Whereas we need to know the rate constant in order to compute the percentages, given the half-life:

[tex]k=\frac{ln(2)}{9hrs}=0.077hrs^{-1}[/tex]

In such a way, we can now compute the fraction in which the reaction has been completed after 3 hrs:

[tex]\frac{A}{Ao}=exp(-0.077hrs^{-1}*3hrs)\\\\\frac{A}{Ao}=0.926[/tex]

And the percent would be 92.6% after multiplying the fraction by 100 %.

Best regards!

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