Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

calculate the [H3O+] of 0.35 M solution of benzoic acid, HC7H3O2

Sagot :

jufsanabriasa

Answer:

4.70x10⁻³ = [H₃O⁺]

Explanation:

The Ka of benzoic acid is 6.3x10⁻⁵

The aqueous equilibrium of benzoic acid with its conjugate base could be written as:

HC₇H₃O₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + C₇H₃O₂(aq)

Where Ka is defined as:

Ka = 6.3x10⁻⁵ = [C₇H₃O₂] [H₃O⁺] / [HC₇H₃O₂]

As both H⁺ and C₇H₃O₂ are obtained from the same equilibrium:

[C₇H₃O₂] = [H₃O⁺]

And as [HC₇H₃O₂] = 0.35M we can write:

6.3x10⁻⁵ = [H₃O⁺] [H₃O⁺] / [0.35M]

2.205x10⁻⁵ = [H₃O⁺]²

4.70x10⁻³ = [H₃O⁺]

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.