Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

calculate the [H3O+] of 0.35 M solution of benzoic acid, HC7H3O2

Sagot :

jufsanabriasa

Answer:

4.70x10⁻³ = [H₃O⁺]

Explanation:

The Ka of benzoic acid is 6.3x10⁻⁵

The aqueous equilibrium of benzoic acid with its conjugate base could be written as:

HC₇H₃O₂(aq) + H₂O(l) ⇄ H₃O⁺(aq) + C₇H₃O₂(aq)

Where Ka is defined as:

Ka = 6.3x10⁻⁵ = [C₇H₃O₂] [H₃O⁺] / [HC₇H₃O₂]

As both H⁺ and C₇H₃O₂ are obtained from the same equilibrium:

[C₇H₃O₂] = [H₃O⁺]

And as [HC₇H₃O₂] = 0.35M we can write:

6.3x10⁻⁵ = [H₃O⁺] [H₃O⁺] / [0.35M]

2.205x10⁻⁵ = [H₃O⁺]²

4.70x10⁻³ = [H₃O⁺]

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.