Answer:
The perimeter is 24 units
Step-by-step explanation:
Given
[tex]A = (-9,2)[/tex] --- [tex](x_1,y_1)[/tex]
[tex]B = (-9,-6)[/tex] --- [tex](x_2,y_2)[/tex]
[tex]C = (-3,-6)[/tex] --- [tex](x_3,y_3)[/tex]
Required
Determine the perimeter
To do this, we calculate the distance AB, BC and AC.
Distance is calculated as:
[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2[/tex]
So, we have:
[tex]AB = \sqrt{(-9 - -9)^2 + (2 - -6)^2[/tex]
[tex]AB = \sqrt{64[/tex]
[tex]AB = 8[/tex]
[tex]BC = \sqrt{(-9 - -3)^2 + (-6 - -6)^2[/tex]
[tex]BC = \sqrt{36[/tex]
[tex]BC = 6[/tex]
[tex]AC = \sqrt{(-9 --3)^2 + (2 --6)^2[/tex]
[tex]AC = \sqrt{100[/tex]
[tex]AC = 10[/tex]
So, the perimeter (P) is:
[tex]P = AB + BC + AC[/tex]
[tex]P =8 + 6 + 10[/tex]
[tex]P =24[/tex]
