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If the center of a circle is at (-7,9) and it’s radius is 5, complete it’s equation: please help will mark brainliest

If The Center Of A Circle Is At 79 And Its Radius Is 5 Complete Its Equation Please Help Will Mark Brainliest class=

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rawnutmeg

Answer:

[tex] {(x + 7)}^{2} + {(y - 9)}^{2} = 25[/tex]

Step-by-step explanation:

[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} [/tex]

[tex] {(x - ( - 7))}^{2} + {(y - 9)}^{2} = {5}^{2} [/tex]

[tex] {(x + 7)}^{2} + {(y - 9)}^{2} = 25[/tex]

The complete equation is ( x -(-7) )² + (y-9)² = 25 .

What is the standard Equation of a Circle ?

The standard Equation of a Circle is given by

( x -h)² + (y-k)² = r²

here , (h,k) is the center of the circle

r is the radius of the circle.

It is given that

center of a circle is at (-7,9)

radius is 5

Therefore the equation of the circle is given by

( x +7)² + (y-9)² = 5²

( x +7)² + (y-9)² = 25

To complete the equation

( x -(-7) )² + (y-9)² = 25

To know more about Standard Equation of a circle

https://brainly.com/question/13658927

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