Answered

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How many moles ofO are present in 3.5 mol of Al2(SO4)3

Sagot :

armandoalturas

Answer:

Name of the compound is aluminum sulphate. chemical formula Al2(SO4)3

In that compound there are two aluminum atoms; three sulphur and 4*3=12 oxygen atoms.

2 oxygen atoms is equivalent to 1 mole oxygen.

so 12 oxygen is equivalent to 12÷2=6 mole oxygen.

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