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How many moles of O are present in 3.5 mol of Al2(SO4)3

Sagot :

aidanbaldobino

Answer:

42 mol

Explanation:

In the problem there are 4 mols of O in the parenthesis but you multiply by 3 since there are 3 moles of SO4, you them times this by 3.5 since there are 3.5 mols of the entire substance.

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