Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
0.131mol
Explanation:
Firstly, we need to find the number of moles of chlorine gas (Cl2) by using the formula:
PV = nRT
Where;
P = pressure (atm)
V = volume (L)
n = number of moles (mol)
R = gas constant (0.0821 Latm/molK)
T = temperature (K)
Using PV = nRT
n of Chlorine = PV/RT
Based on the information provided in this question, V = 2.12 L, P = 2.27atm, T = 24°C = 24 + 273 = 297K
n = 2.27 × 2.12/ 0.0821 × 297
n = 4.8124/24.3837
n = 0.197
number of moles of Chlorine gas = 0.197mol
The balanced chemical equation provided in this question is as follows;
2 Al(s) + 3Cl2 (g) → 2AlCl3 (s)
3 moles of Cl2 produce 2 moles of AlCl3
0.197moles of Cl2 will produce;
0.197 × 2/3
= 0.394/3
= 0.131mol of AlCl3.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.