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Answered

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A solution contains 6.30 x 10-2 g of oxalic acid, H2C204 - 2
H20, in 250 mL. What is the molarity (M) of this solution?

Sagot :

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Answer: c= 1.99·10^-3 mol/l

Explanation: molar mass of oxalis acid is M=126.068 g/mol.

V= 0.25 l and mass is 0.063 g

Amount of substance n = m/ M = cV

Molality c = m/MV

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