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find the product of reciprocal of 9/11 and the additive inverse of -18/55​

Sagot :

Answer:

[tex]\frac{2}{5}[/tex]

Step-by-step explanation:

The reciprocal of [tex]\frac{9}{11}[/tex] is [tex]\frac{11}{9}[/tex]

The additive inverse of - [tex]\frac{18}{55}[/tex] is [tex]\frac{18}{55}[/tex] , then

[tex]\frac{11}{9}[/tex] × [tex]\frac{18}{55}[/tex] ( cancel 11 and 55 by 11 and 9 and 18 by 9 )

= 1 × [tex]\frac{2}{5}[/tex]

= [tex]\frac{2}{5}[/tex]