vishnuvedpolavarupu
Answered

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1.
The equation of the line having x-intercept -3/2, y-intercept 3/4 is
1) 3x + 2y - 6 = 0
2) 2x - 4y + 3 = 0
3) 2x + 3y - 5 = 0
4) 4x - 3y - 12 = 0
O
1)
2)
O
3)
O
4)​

Sagot :

Answer:

2nd option

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- [tex]\frac{3}{2}[/tex], 0) and (x₂, y₂ ) = (0, [tex]\frac{3}{4}[/tex] )

m = [tex]\frac{\frac{3}{4}-0 }{0+\frac{3}{2} }[/tex] = [tex]\frac{\frac{3}{4} }{\frac{3}{2} }[/tex] = [tex]\frac{1}{2}[/tex] and c = [tex]\frac{3}{4}[/tex] , then

y = [tex]\frac{1}{2}[/tex] x + [tex]\frac{3}{4}[/tex] ( multiply through  by 4 to clear the fractions )

4y = 2x + 3 ( subtract 4y from both sides )

0 = 2x - 4y + 3 , that is

2x - 4y + 3 = 0 ← equation of line

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