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calculate the mass of NaOH required to prepare 88.25mL of 0.155M solution

Sagot :

swekshyakarna738

Answer:

its 0.547g

Explanation:

for normality; we have W=(NEV)/1000

similarly for molarity; we have W= (MMwV)/1000

here the molarity is given... molecular weight of NaOH is 40 and the volume to be prepared is 88.25 ML so by formula, we have W=(0.155×40×88.25)/1000 which is equal to 0.547g. Hence, W=0.547g

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