Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

calculate the mass of NaOH required to prepare 88.25mL of 0.155M solution

Sagot :

swekshyakarna738

Answer:

its 0.547g

Explanation:

for normality; we have W=(NEV)/1000

similarly for molarity; we have W= (MMwV)/1000

here the molarity is given... molecular weight of NaOH is 40 and the volume to be prepared is 88.25 ML so by formula, we have W=(0.155×40×88.25)/1000 which is equal to 0.547g. Hence, W=0.547g

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.