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A disc of moment of inertia 45kgm^2 is rotating with an angular velocity of 12rad/s.what will be its rotational kinetic energy?​

Sagot :

swekshyakarna738

Answer:

3240 J

Explanation:

here moment of inertia (I)= 45kgm²

angular velocity (ω) = 12 rad/s

now KE = 1/2(Iω²)=1/2(45×12²)= 3240J

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