Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squared, plus, 32 has a known factor of (x-4)(x−4)left parenthesis, x, minus, 4, right parenthesis. Rewrite p(x)p(x)p, left parenthesis, x, right parenthesis as a product of linear factors.

Sagot :

abidemiokin

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Given p(x) = x^3-6x^2+32 when it is divided by  x - 4, the quotient gives

x^2-2x-8

Q(x) = P(x)/d(x)

x^3-6x^2+32/x- 4  =  x^2-2x-8

Factorizing the quotient

x^2-2x-8

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)

pie1111111124

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.