Draw the product you expect from the reaction of (R)-2-bromooctane with -CN. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include H atoms at chiral centers only. If a group is achiral, do not use wedged or hashed bonds on it.

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03-04-2021
Chemistry

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Draw the product you expect from the reaction of (R)-2-bromooctane with -CN. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include H atoms at chiral centers only. If a group is achiral, do not use wedged or hashed bonds on it.

Sagot :

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2021-04-04T15:36:22-04:00

pstnonsonjoku pstnonsonjoku

04-04-2021

Answer:

See explanation and image attached

Explanation:

The reaction between (R)-2-bromooctane and -CN^- is an SN2 reaction. An SN2 reaction involves a synchronous attack of the nucleophile as the leaving group is departing.

This leads to a five member transition state in which a bond is being broken and another is being made. Since the nucleophile attacks from the backside, SN2 mechanism leads to inversion of configuration as shown in the image attached.

Answer Link

Draw the product you expect from the reaction of (R)-2-bromooctane with -CN. Use the wedge/hash bond tools to indicate stereochemistry where it exists. Include H atoms at chiral centers only. If a group is achiral, do not use wedged or hashed bonds on it.

Sagot :

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