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Which statement about k(x)=-x2-2x+15 is true?

A The zeros are -3 and 5, because k(x)= -(x + 3)(x - 5).
B The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).
C The zeros are -5 and -3, because k(x)= -(x + 5)(x + 3).
D The zeros are 3 and 5, because k(x)= -(x - 3)(x - 5).​

Sagot :

altavistard

Answer:

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The function k(x)=-x2-2x+15 can be re-written as k(x) = -x^2 - 2x + 15, which in turn becomes -(x^2 + 2x - 15) after the negative sign is factored out.

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

Thus, Answer B is correct:  

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Answer:

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

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