suiii
Answered

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A. 92%
B. 29%
C. 23%
D. 100%

Branliest to correct answer explain how you solved please


A 92 B 29 C 23 D 100 Branliest To Correct Answer Explain How You Solved Please class=

Sagot :

[tex]\huge\mathfrak\blue{answer}[/tex]

[tex]c) \: 23\%[/tex]

Let's figure out how many pieces of candy there is in total:

10 + 12 + 6 = 28

In total, there are 28 pieces of candy.

Let's find the probability that a piece is sour:

[tex] \frac{10}{28} = \frac{5}{14} [/tex]

The probability of pulling a sour piece out of the bag is 5/14.

This means that the probability that the candy pulled is not sour is 9/15 (or simplified 3/5)

To find the probability that the first candy picked out is sour AND the second candy picked is not sour we have to multiply the probabilities of both:

[tex] \frac{5}{14} * \frac{3}{5} = 0.229 = 23\%[/tex]

[tex]\huge\sf\blue{thank \: you}[/tex]

(Brainliest would be appreciated :))

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