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Sagot :
Given:
The equation of a line is
[tex]y=-4x+10[/tex]
A perpendicular line on the given line passes through the point (4,-6).
To find:
The equation of the perpendicular line.
Solution:
We have,
[tex]y=-4x+10[/tex]
On comparing this equation with slope intercept form [tex]y=mx+b[/tex], we get
[tex]m=-4[/tex]
So, the slope of the given line is -4.
We know that the product of slopes of two perpendicular lines is always -1.
[tex]m\times m_1=-1[/tex]
[tex](-4)\times m_1=-1[/tex]
[tex]m_1=\dfrac{-1}{-4}[/tex]
[tex]m_1=\dfrac{1}{4}[/tex]
The slope of the required line is [tex]\dfrac{1}{4}[/tex] and it passes through the point (4,-6). So, the equation of the line is
[tex]y-y_1=m_1(x-x_1)[/tex]
[tex]y-(-6)=\dfrac{1}{4}(x-4)[/tex]
[tex]y+6=\dfrac{1}{4}x-1[/tex]
[tex]y=\dfrac{1}{4}x-1-6[/tex]
[tex]y=\dfrac{1}{4}x-7[/tex]
Therefore, the correct option is B.
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