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A tiger leaps horizontally from a 6.5 m tall rock with a speed of 3.5 ms. How many seconds will it take for her to land?

Sagot :

Answer: 1.15 s

Explanation:

Given

Height of rock h=6.5 m

The horizontal speed of tiger u=3.5 m/s

In the vertical direction, there is no initial speed

Using the equation of motion

[tex]\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s[/tex]

Time taken is 1.15 s