Answered

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What is the equation of the axis of symmetry for this function? H(x) = -X2 + 10x - 11 x = -5 0 x= -10 x = 5 x = 10

Sagot :

Given:

The equation of a quadratic function is:

[tex]H(x)=-x^2+10x-11[/tex]

To find:

The equation of the axis of symmetry for the given function.

Solution:

If a quadratic function is [tex]f(x)=ax^2+bx+c[/tex], then the equation of the axis of symmetry is:

[tex]x=-\dfrac{b}{2a}[/tex]        ...(i)

We have,

[tex]H(x)=-x^2+10x-11[/tex]

Here, [tex]a=-1,b=10,c=-11[/tex]. So, the equation of axis of symmetry by using (i), is

[tex]x=-\dfrac{10}{2(-1)}[/tex]

[tex]x=-\dfrac{10}{-2}[/tex]

[tex]x=5[/tex]

Therefore, the correct option is C.

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