Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Ask your questions and receive precise answers from experienced professionals across different disciplines. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

How many grams of iron contain 4.06X10^24 atoms of iron?

Sagot :

4.06x20^24/6.02x10^23 = 6.744 moles x 55.845 g/mole = 376.61868grams
okpalawalter8

We have that the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

From the question we are told

How many grams of iron contain 4.06X10^24 atoms of iron?

Generally the equation for the Moles of Iron   is mathematically given as

[tex]M=\frac{4.06x10^24}{6.02x10^23} \\\\M=6.744moles[/tex]

Therefore

Where Molar mass of Iron =55.845

Generally the equation for the mass   is mathematically given as

g= 6.744  x 55.85

g= 376.6g

Therefore

the grams of iron contained 4.06X10^24 atoms of iron is

g= 376.6g

 

For more information on this visit

https://brainly.com/question/17756498

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.