Answer:
1) F = 8.789 10² N, 2) F = 1.5 10⁴ N
Explanation:
We can solve this exercise using Coulomb's law
F =[tex]k \frac{q_1q_2}{r^2}[/tex]
Knowing that charges of the same sign repel
let's apply this equation to our case
1) the charges are q = - 0.0025 C and the distance between them r = 8 m
we calculate
F = 9 10⁹ 0.0025 0.0025 /8²
F = 8.789 10² N
as the two charges are of the same sign the force is repulsive
2) q₁ = -0.004C and q₂ = -0.003 C with a distance of r = 3.0 m
we calculate
F = 9 10⁹ 0.004 0.003 / 3²
F = 1.5 10⁴ N
