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Consider functions fand g.
f(1) = (1 + 1)
g(x) = 3 + 1
Evaluate the function composition.
(fog)(-64) =

Sagot :

abidemiokin

Answer:

f(g(-64)) = -190

Step-by-step explanation:

The functions are not well written.

Let us assume;

f(x) = x+1

g(x) = 3x+1

f(g(x)) = f(3x+1)

Replace x with 3x+1 in f(x)

f(g(x)) = (3x+1) + 1

f(g(x)) = 3x + 2

f(g(-64)) = 3(-64) + 2

f(g(-64)) = -192+2

f(g(-64)) = -190

Note that the functions are assumed but same method can be employed when calculating composite functions

Using composite functions, it is found that:

  • [tex](f \circ g)(-64) = -8[/tex]

The composite function of functions f(x) and g(x) is given by:

[tex](f \circ g)(x) = f(g(x))[/tex]

Researching the problem on the internet, it is found that the functions are:

[tex]f(x) = (x + 1)^3[/tex]

[tex]g(x) = \sqrt[3]{x} + 1[/tex]

Then, the composite function is:

[tex](f \circ g)(x) = f(g(x)) = f(\sqrt[3]{x} + 1) = (\sqrt[3]{x} + 1 + 1)^3 = (\sqrt[3]{x} + 2)^3[/tex]

At x = -64, we have that:

[tex](f \circ g)(-64) = (\sqrt[3]{-64} + 2)^3 = (-4 + 2)^3 = (-2)^3 = -8[/tex]

Hence:

  • [tex](f \circ g)(-64) = -8[/tex]

To learn more about composite functions, you can take a look at https://brainly.com/question/17684028

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