Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

In ΔJKL, l = 860 inches, j = 920 inches and ∠K=126°. Find ∠L, to the nearest degree.

Sagot :

Answer:

26

Step-by-step explanation:

JKL= ABC,  jkl=abc

1.) use law of sines to find k.

[tex]c^{2} =a^{2} +b^{2} -2abCosC[/tex]    

[tex]c=\sqrt{920^{2} +860^{2} -2(920)(860)cos(126) } = 1586.225515[/tex]

2.) use law of cosines to find L

[tex]\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}[/tex]  

plug in for b and c:  [tex]\frac{860}{sinB} =\frac{1586.225515}{sin126}[/tex]

cross multiply: [tex]\frac{1586.23sinB}{1586.23} =\frac{860sin126}{1586.23}[/tex]

[tex]sinB= 0.4386227612\\B=sin^-1(0.4386227612)= 26.01604086\\[/tex]

L=26

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.