Answered

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An object is placed perpendicular to the the principal axis of convex lens of focal length 8,the distance of the object from the lens is 12cm .Find the position &nature of the image​

Sagot :

Answer:

v = 24 cm and inverted image

Explanation:

Given that,

The focal length of the object, f = +8 cm

Object distance, u = -12 cm

We need to find the position &nature of the image​. Let v be the image distance. Using lens formula to find it :

[tex]\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex]

Put all the values,

[tex]\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm[/tex]

So, the image distance from the lens is 24 cm.

Magnification,

[tex]m=\dfrac{v}{u}\\\\m=\dfrac{24}{-12}\\\\m=-2[/tex]

The negative sign of magnification shows that the formed image is inverted.

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